x+36-64x^2=0

Solution for x+36-64x^2=0 equation:

x+36-64x^2=0

a = -64; b = 1; c = +36;
Δ = b2-4ac
Δ = 12-4·(-64)·36
Δ = 9217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{9217}}{2*-64}=\frac{-1-\sqrt{9217}}{-128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{9217}}{2*-64}=\frac{-1+\sqrt{9217}}{-128}
$